(a) One easy way khổng lồ find the limiting reactant in a reaction is to lớn divide the moles of each reactant by the corresponding coefficient in the balanced equation. In the current problem, 1 is the coefficient for both Cu
SO4 & for Na2S, so we simply divide the moles of each by one, & see which is less:
mols Cu
SO4 = 6 ml x 1 L/ 1000 ml x 1.0 mol/L = 0.006 mols Cu
SO4
mols Na2S = 8 ml x 1 L / 1000 ml x 1.0 mol/L = 0.008 mols Na2S
Cu
SO4 is the limiting reactant
(b) khổng lồ calculate theoretical yield, we use the limiting reactant khổng lồ determine how much hàng hóa can be made:
0.006 Cu
SO4 x 1 mol Cu
S / mol Cu
SO4 x 95.6 g /mol Cu
S = 0.57 g Cu
S (2 sig. Figs.)
(c) to lớn find % yield, we divide the actual yield (0.250 g) by the theoretical yield & convert lớn %:
0.250 g / 0.57 g (x100) = 44% (2 sig. Figs.)
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| Enter a chemical equation to balance: |
| Error: equation Cu SO4+Na2S=Cu2S+Na2SO4 is an impossible reactionPlease correct your reaction or click on one of the suggestions below: Cu SO4 + Na2S = Cu S + Na2SO4Instructions and examples below may help khổng lồ solve this problem You can always ask for help in the diễn đàn |
| Instructions on balancing chemical equations:Enter an equation of a chemical reaction and click "Balance". The answer will appear below Always use the upper case for the first character in the element name & the lower case for the second character.Examples: Fe, Au, Co, Br, C, O, N, F. Compare: co - cobalt and CO - carbon monoxide To enter an electron into a chemical equation use - or e lớn enter an ion, specify charge after the compound in curly brackets: +3 or 3+ or 3. Example: Fe3+ + I- = Fe2+ + I2Substitute immutable groups in chemical compounds to lớn avoid ambiguity. For instance equation C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but Ph C2H5 + O2 = Ph OH + CO2 + H2O will Compound states |
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